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Re: Variable stride in array indices
- To: "Kenneth P. Bowman" <bowman(at)null.tamu.edu>
- Subject: Re: Variable stride in array indices
- From: Liam Gumley <Liam.Gumley(at)ssec.wisc.edu>
- Date: Fri, 07 May 1999 08:50:24 -0500
- Newsgroups: comp.lang.idl-pvwave
- Organization: Space Science and Engineering Center, University of Wisconsin-Madison
- References: <bowman-0705990718310001@tl6-218-141.tca.net>
- Xref: news.doit.wisc.edu comp.lang.idl-pvwave:14652
Kenneth P. Bowman wrote:
> We haven't had a good argument about IDL syntax lately, so I thought I
> would ask why IDL does not allow variable stride in array indices.  For
> example, if
> 
> zz = z[0:5:2]
> 
> then zz would contain [z[0], z[2], z[4]].
> 
> I realize that this kind of thing can be done with array subscript lists
> such as z[[0, 2, 4]], but this can be awkward for multidimensional
> arrays.  It is also necessary to *store* the lists of subscripts, and I
> believe that implementation through indirect subscripts must be slower
> than implementing strides through direct iteration (i.e., internal
> compiled DO loops).
In fact we had a good argument recently here at SSEC about indexing 2D
arrays with variable stride. The argument was this: If I have an array
a, and an index array x, why doesn't a[x,x] extract a 2D subsampled
array? (it returns a 1D array).
Here's what we resolved:
Say I want to extract every 2nd row and column of an array:
IDL> a=indgen(10,10)
First, I create the index array:
IDL> x=indgen(5)*2
IDL> print,x
       0       2       4       6       8
I can select the columns:
IDL> print,a[x,*]
       0       2       4       6       8
      10      12      14      16      18
      20      22      24      26      28
      30      32      34      36      38
      40      42      44      46      48
      50      52      54      56      58
      60      62      64      66      68
      70      72      74      76      78
      80      82      84      86      88
      90      92      94      96      98
Or I can select the columns and rows at the same time:
IDL> print,(a[x,*])[*,x]
       0       2       4       6       8
      20      22      24      26      28
      40      42      44      46      48
      60      62      64      66      68
      80      82      84      86      88
This is equivalent to the following
IDL> a=a[x,*]
IDL> print,a
       0       2       4       6       8
      10      12      14      16      18
      20      22      24      26      28
      30      32      34      36      38
      40      42      44      46      48
      50      52      54      56      58
      60      62      64      66      68
      70      72      74      76      78
      80      82      84      86      88
      90      92      94      96      98
IDL> a=a[*,x]
IDL> print,a
       0       2       4       6       8
      20      22      24      26      28
      40      42      44      46      48
      60      62      64      66      68
      80      82      84      86      88
Cheers,
Liam.
---
Liam E. Gumley
Space Science and Engineering Center, UW-Madison
http://cimss.ssec.wisc.edu/~gumley