# Generally accessing the rest of the elements in an array

• Subject: Generally accessing the rest of the elements in an array
• From: "tbowers" <tbowers(at)nrlssc.navy.mil>
• Date: Tue, 20 Feb 2001 16:58:47 -0600
• Newsgroups: comp.lang.idl-pvwave
• Organization: Naval Research Laboratory, Washington, DC
• Xref: news.doit.wisc.edu comp.lang.idl-pvwave:23596

```How do I access the 2nd + dimensions of an array generally, without knowing
the
number of higher dims this array has. E.g. say a is a 3 column by
n-dimensional
aray, and n is unknown. Here, I'll define it as:

a = indgen(3,2,4)

I want the equivalent of (in this case):
b = (a[0,*,*])^2 + (a[1,*,*])^2 + (a[2,*,*])^2

but this requires *'ing the correct dimensions ([0,*,*] for 3 dims,
[0,*,*,*] for 4 dims
etc). What I need is a general way to access the "rest" of the data, as Paul
Harvey
would say.

Actually, what I *really* want is to access it all generally so if a is 3
columns, it'll be
as above

b = (a[0,*,*])^2 + (a[1,*,*])^2 + (a[2,*,*])^2
but if it's 4 columns, it'll be
b = (a[0,*,*])^2 + (a[1,*,*])^2 + (a[2,*,*])^2 + (a[3,*,*])^2
5 columns...
b = (a[0,*,*])^2 + (a[1,*,*])^2 + (a[2,*,*])^2 + (a[3,*,*])^2 + (a[4,*,*])^2
n columns...
b = (a[0,*,*])^2 + (a[1,*,*])^2 + (a[2,*,*])^2 + ... + (a[n-1,*,*])^2

but I don't think this is possible without a for loop.

Anyway, back to the ranch. I do know that i could ask the data and select in
a case
or if then else block like

if (nDims eq 2) then b = b = (a[0,*])^2 + (a[1,*])^2 + (a[2,*])^2
else if (nDims eq 3) then b = (a[0,*,*])^2 + (a[1,*,*])^2 + (a[2,*,*])^2
else if (nDims eq 4) then b = (a[0,*,*,*])^2 + (a[1,*,*,*])^2 +
(a[2,*,*,*])^2

but I'm really doing other stuff in here too, and each of these cases would
end up
having about 10 cases *within* those cases. Uuuuugly.

I tried variants of
a[0, *]
but I can't figure it out.

tia,
todd

```