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long to float
- Subject: long to float
- From: "Dominik" <dpaul(at)ukl.uni-freiburg.de>
- Date: Thu, 5 Apr 2001 16:54:12 +0200
- Newsgroups: comp.lang.idl-pvwave
- Organization: Rechenzentrum der Universitaet Freiburg, Germany
- Xref: news.doit.wisc.edu comp.lang.idl-pvwave:24399
Hello,
I have a small problem (i hope)
I read a number (is = -536852787) out of a file. But this number is not a
long, it shoul be a float. It should be sb =6588.00. I am not sure if the
first Number is a big endian, but the second is in little endian.
so, after I multiply the start number with -1 and make byteorder, the same
hexadecimal number is in the memory. It is FF1F33B9, but he shows
e -14732359
Is there a good way to see the stuff in memory as a float and not as a
long??
thanks for helping
Dominik
Example code
pro test
f = -536852787
help, f
print, Format='(Z)', f
f = -1 * f
help, f
print, Format='(Z)', f
byteorder, f
help, f
print, Format='(Z)', f
end