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Re: passing structure elements... by value?
- Subject: Re: passing structure elements... by value?
- From: Vince Hradil <hradilv(at)yahoo.com>
- Date: Tue, 17 Jul 2001 15:54:16 GMT
- Newsgroups: comp.lang.idl-pvwave
- Organization: Abbott Labs Pharmaceutical Products Division
- References: (
- User-Agent: Opera/5.11 (Windows NT 4.0; U) [en]
- Xref: news.doit.wisc.edu comp.lang.idl-pvwave:25716
Not sure this is a structure issue, but instead an array issue!
Array elements are passed by value. Instead you have to do:
IDL> struct = {A:0, B:0} & big = replicate(struct,3)
IDL> tmpbig = big[0]
IDL> test, tmpbig
IDL> big[0] = tmpbig
IDL> print, big
{ 1 1}{ 0 0}{ 0 0}
Or how about changing your pro to a function?
function test, mod_struct
for i=0, n_tags(mod_struct)-1 do begin
mod_struct.(i) = mod_struct.(i) + 1
endfor
return, mod_struct
end
then do:
IDL> struct = {A:0, B:0} & big = replicate(struct,3)
IDL> big[0] = test(big[0])
IDL> print, big
{ 1 1}{ 0 0}{ 0 0}
NB I haven't tested any of the above code, since I am away from my "IDL computer" at the moment ;^)
On Fri, 13 Jul 2001 17:03:39 +0100, Randall Skelton <rhskelto@atm.ox.ac.uk> wrote:
> Hi all,
>
> I am seem to be somewhat confused on passing structure... this *almost*
> seems like one of those dreaded 'pass by reference/pass by value'
> problems...
>
> I have a simple routine that increments the value of a structure:
>
> pro test, mod_struct
> for i=0, n_tags(mod_struct)-1 do begin
> mod_struct.(i) = mod_struct.(i) + 1
> endfor
> end
>
> As expected, this will increment all of the values in a passed structure.
>
> IDL> struct = {A:0, B:0} & big = replicate(struct,3)
> IDL> print, big
> { 0 0}{ 0 0}{ 0 0}
> IDL> test, big
> IDL> print, big
> { 1 1}{ 1 1}{ 1 1}
>
> But, when I try and increment a single element in the structure it fails?
>
> IDL> struct = {A:0, B:0} & big = replicate(struct,3)
> IDL> test, big[0]
> IDL> print, big
> { 0 0}{ 0 0}{ 0 0}
> ^^^^^^^^^^^^^^^^^^
>
> I expected the ^^ element above to be ones? Is there any way to force IDL
> to pass this by reference instead of passing by value? It would be nice if
> you could put brackets around the thing you want to pass by reference...
> something like '(big[0])'
>
> Have a good weekend all!
> Randall
>
> PS: I'm sure Liam's new book answers this...
>