# Re: Interpolation question

```rkj@dukebar.crml.uab.edu (R. Kyle Justice) writes:

>I have an image containg some bad values.  I would like
>to replace these points with the average value of their
>neighbors.  Is there an easy way to do this without loops?

>For instance, a 3x3 array as follows:

>1 1 1
>1 0 1
>1 1 1

>would become

>1 1 1
>1 1 1
>1 1 1.

One way to do this would be something like the following.

SZ = SIZE(ARRAY)
NX = SZ(1)
NY = SZ(2)
GOOD = ARRAY EQ ARRAY		;Bad points are NaN
TEMP = ARRAY*GOOD
WBAD = WHERE(GOOD EQ 0, COUNT)
IF COUNT GT 0 THEN BEGIN
ARRAY[I,J] = (TEMP[I-1,J-1] + TEMP[I,J-1] + TEMP[I+1,J-1] + \$
TEMP[I-1,J] + TEMP[I+1,J] + TEMP[I-1,J+1] + TEMP[I,J+1] + \$
TEMP[I+1,J+1]) / (GOOD[I-1,J-1] + GOOD[I,J-1] + \$
GOOD[I+1,J-1] + GOOD[I-1,J] + GOOD[I+1,J] + GOOD[I-1,J+1] + \$
GOOD[I,J+1] + GOOD[I+1,J+1])
ENDIF

>I can't get the boundary conditions to work correctly when
>I use CONVOL.  It either zeros the edges or does not process
>them.

This doesn't really trip the boundary quite right either, because some points
will be more heavily weighted than others.  But it does get the job done.  You
can modify it with more WHERE() statements, to treat the points at the
edges separately.

William Thompson
```