Re: Faster than this...

[Ricardo Fonseca <zamb(at)physics.ucla.edu>]

Nope, not a trick question, just a vary basic one

Thanks, Ricardo


> From: Craig Markwardt <craigmnet@cow.physics.wisc.edu>
> Organization: U. Wisc. Madison Physics -- Compact Objects
> Reply-To: craigmnet@cow.physics.wisc.edu
> Newsgroups: comp.lang.idl-pvwave
> Date: 03 Feb 2000 19:00:34 -0600
> Subject: Re: Faster than this...
> 
> 
> Ricardo Fonseca <zamb@physics.ucla.edu> writes:
>> 
>> I have this line of code in IDL 5.2a
>> 
>> for j=0, N-1 do Data[j]=XAxisData[j]^2*Data[j]
>> 
>> Where both Data and XAxisData have the same dimension N.
>> Does anyone know if there is a faster way of doing this
>> (i.e. avoiding the for cicle) ?
> 
> I hope this isn't a trick question.  The expression
> 
> Data = XAxisDAta^2 * Data
> 
> should work fine.  Don't worry about Data being overwritten.  The
> right hand side is fully evaluated with the "old" value of Data,
> before the "new" value of Data is assigned.
> 
> Craig
> 
> -- 
> --------------------------------------------------------------------------
> Craig B. Markwardt, Ph.D.         EMAIL:    craigmnet@cow.physics.wisc.edu
> Astrophysics, IDL, Finance, Derivatives | Remove "net" for better response
> --------------------------------------------------------------------------